If A=6 and B=5, what is the value of (A^2-B^2)^2?

If A=6 and B=5, what is the value of (A^2-B^2)^2?

• A. 25
• B. 81
• C. 121
• D. 49

Answer: (C)

To find the value of \((A^2 - B^2)^2\) given that \(A = 6\) and \(B = 5\), we start by calculating the individual components. First, calculate \(A^2\) and \(B^2\): - \(A^2 = 6^2 = 36\) - \(B^2 = 5^2 = 25\) Now, subtract \(B^2\) from \(A^2\): \[ A^2 - B^2 = 36 - 25 = 11 \] Next, we need to square the result of \(A^2 - B^2\): \[ (A^2 - B^2)^2 = 11^2 = 121 \] This calculation shows that the resulting value of \((A^2 - B^2)^2\) is indeed 121. Thus, this corresponds with the answer provided. The formula used here is a straightforward application of arithmetic operations, highlighting how to manipulate exponents and perform basic algebraic operations to get to the final answer.

To find the value of ((A^2 - B^2)^2) given that (A = 6) and (B = 5), we start by calculating the individual components.

First, calculate (A^2) and (B^2):

• (A^2 = 6^2 = 36)

• (B^2 = 5^2 = 25)

Now, subtract (B^2) from (A^2):

[

A^2 - B^2 = 36 - 25 = 11

]

Next, we need to square the result of (A^2 - B^2):

[

(A^2 - B^2)^2 = 11^2 = 121

]

This calculation shows that the resulting value of ((A^2 - B^2)^2) is indeed 121. Thus, this corresponds with the answer provided. The formula used here is a straightforward application of arithmetic operations, highlighting how to manipulate exponents and perform basic algebraic operations to get to the final answer.